???

def my_function(): print("Hello from a function") my_function() def my_function(fname): print(fname + " Refsnes") my_function("Emil") my_function("Tobias") my_function("Linus")

!!!

def add(a, b): return a + b

565656

Please under 1000 chars

abcdefghijklmnopqrstuvwxyz

def abc(): return "abcdefghijklmnopqrstuvwxyz" abc()

how to get your iq

def get_iq(a, b): return (a + b)/2 get_iq(192, 176)

!!!

def a(): print(x) x = 2 a()

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def sim_food(food_produce): food = 100 iron = 100 for time in range(0,600,10): food = food + food_produce food = food - (time/60) if food < 0: return 'you died' return 'you survived'

import Allen Allen.Allen()

The function Allen.Allen() prints the string "Allen is awesome"

!!!

111

def name(name): return name name("Sherry")

!!!

def f(a, b): return a + b

!!!

motor(1,0)

Python

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.

food = 100 iron = 100 def food_per_second(time): return time / 10 def iron_per_second(time): return time / 100 def food_iron_counter(time): global food global iron food = food - food_per_second(time) iron = iron - iron_per_second(time) return food, iron food_iron_counter(10)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.

food = 100 iron = 100 time = 0 def send_supplies(): global food global iron global time food = food - 1 iron = iron - 1 time = time + 10 def produce_food(): global food global time food = food + 1 time = time + 100 def produce_iron(): global iron global time iron = iron + 1 time = time + 100 def check_for_death(): global food global iron if food <= 0 and iron <= 0: print("You are dead") print("The army is dead") exit() elif food <= 0: print("You are dead") print("The army is still alive") exit() elif iron <= 0: print("You are still alive") print("The army is dead") exit() send_supplies() produce_food() produce_iron()

def chk_odd(num): if num % 2 == 0: return True else: return False

The function chk_odd takes one argument num and checks if it is an odd number. If yes it returns true and else it returns false

the 1 to 19 times table

for i in range(1, 20): for j in range(1, 20): print(i * j)

the 1 to 19 times table

def times(number): for i in range(1, 21): print(number * i) times(1)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.

food = 100 iron = 100 timestep = 0 max_time = 100000 while food > 0 and iron > 0 and timestep < max_time: time.sleep(10) food = food + 1 time.sleep(100) iron = iron + 1 time.sleep(60) food = food - 1 timestep = timestep + 1 print(food, iron, timestep)

how to get your iq

def iq(a, b, c): return (a + b + c)/3

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.

def army(): food = 100 iron = 100 for i in range(0, 100000): food -= 1/60 iron -= 1/100 if food <= 0 or iron <= 0: return "you have died" return "you have survived" army()

GRADE 3 SASMO 2023 简体 （Examination time is:2023-04-08 14:00） 姓名:陈艾纶 准考证号:086230002639 手机:15300601005 There is still a long way to go 01 min 25 s Waiting for the exam

def grade(score): if score > 100 or score < 0: return "error" elif score >= 89: return "A" elif score >= 79: return "B" elif score >= 69: return "C" elif score >= 59: return "D" else: return "E" print(grade(80))

import time import random print('you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food.') def ac (x,y) f=x i=y print('food:'f 'iron:'i) def gc (x) if f<=0: print('fail!')

### Basic usage

for i in range(1, 20): for j in range(1, 20): print(i * j)

for i in range(1, 20): for j in range(1, 20): if j > i: print(i * j)

sing the song never gonna give you up

def sing(): return "never gonna give you up" sing()

the 1 to 19 times table

def times_table(a): return [[i*a for i in range(1, 20)]] times_table(5)

and the square numbers of 19 times times table

for i in range(1, 20): print(f'{i} x {i} = {i*i}')

251 GB Storage

def storage(gb): return gb * 1000 storage(1)

and the square numbers of 999 times times table

def square(x): return x * x def times_table(n): for i in range(1, n + 1): print(i, "times table") for j in range(1, n + 1): print(i, "*", j, "=", i * j) print() times_table(999)

251 GB Storage

3 def GB_to_KB(a): return a * 1024 * 1024 * 1024

the 1 to 19 times table

def times(n): return n * 19 print(times(1)) print(times(2)) print(times(3)) print(times(4)) print(times(5)) print(times(6)) print(times(7)) print(times(8)) print(times(9)) print(times(10)) print(times(11)) print(times(12)) print(times(13)) print(times(14)) print(times(15)) print(times(16)) print(times(17)) print(times(18)) print(times(19)) print(times(20))

how to get your iq

def iq(a, b, c): return (a + b + c) iq(1, 2, 3)

999 times times table

def table(num): for i in range(1,11): print(f"{num} x {i} = {num*i}") table(999)

!!!

def square(a): return a * a

the 1 to 19 times table

func times(a: Int, b: Int) -> Int { return a * b } times(1, b:19)

def chk_odd(num): if num % 2 == 0: return True else: return False

chk_odd is a function that takes one parameter num and returns whether the parameter is an odd or not.

the 1 to 19 times table

package main import "fmt" type Num int func main() { for i := 1; i <= 19; i++ { //fmt.Println(i * 1) //fmt.Println(i * 2) //fmt.Println(i * 3) //fmt.Println(i * 4) //fmt.Println(i * 5) //fmt.Println(i * 6) //fmt.Println(i * 7) //fmt.Println(i * 8) //fmt.Println(i * 9) //fmt.Println(i * 10) //fmt.Println(i * 11) //fmt.Println(i * 12) //fmt.Println(i * 13) //fmt.Println(i * 14) //fmt.Println(i * 15) //

251 GB Flash Storage

def convert_storage(size): unit=['KB', 'MB', 'GB', 'TB'] i=0 while size > 1024: size /= 1024 i += 1 return str(size) + unit[i] print(convert_storage(1099511627776)) # Should be 1 TB

def food_timer(food,seconds): return food + int(seconds / 10) def iron_timer(iron,seconds): return iron + int(seconds / 100) def army_timer(food,seconds): return food - int(seconds / 60) def survival(food, iron, seconds): army = True while army: print(food,iron) food = food_timer(food,seconds) iron = iron_timer(iron,seconds) food = army_timer(food,seconds) if food <= 0: print('You are dead') army = False if iron <= 0: print('You lost the war') army = False survival(100,100,100000)

The function survival takes three arguments food, iron, and seconds. Define the variable army to True and create a while loop. The while loop takes the food, iron, and seconds. The while loop prints the value of food and iron. The while loop uses the function food_timer, iron_timer, and army_timer to update the value of food and iron. If the value of food is less than or equal to zero print 'You are dead'. If the value of iron is less than or equal to zero print 'You lost the war.

GRADE 3 SASMO 2023 简体 （Examination time is:2023-04-08 14:00） 姓名:陈艾纶 准考证号:086230002639 手机:15300601005 There is still a long way to go 01 min 25 s Waiting for the exam

def add(a, b): return a + b add(1, 2)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def army(food, iron, food_production, iron_production): while True: if food < 0: return "You died." else: food_production = food_production + 10 iron_production = iron_production + 100 food = food - 1 if food_production == 10: food = food + 1 food_production = 0 if iron_production == 100: iron = iron + 1 iron_production = 0 return "food = %s , iron = %s" % (food, iron) food = 100 iron = 100 food_production = 0 iron_production = 0 army(food, iron, food_production, iron_production)

!!!

def new_line(): print("") new_line()

the 1 to 19 times table

def times(n): for i in range(1, 20): print(i, '*', n, '=', i * n) times(5)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def survival(food, iron): seconds = 0 while food > 0 and iron > 0: seconds += 1 food -= 1/60 iron -= 1/1000 if seconds % 10 == 0: food += 1 if seconds % 100 == 0: iron += 1 if food <= 0: print("you die of starvation") if iron <= 0: print("you die of iron deficiency")

the 1 to 19 times table

def times(n): for i in range(1, 20): print(n, 'x', i, '=', n*i) times(3)

and the square numbers of 999 times times table

def times_table(n): for i in range(1, 10): print(n * i) times_table(999)

j

def f(x, y): if x > y: return x else: return y

!!!

def add_one(a): return a + 1 add_one(10) # Write a function called add_one that adds 1 to its input and returns that output >>> def add_one(num): ... return num + 1 ... >>> add_one(10) 11

!!!

def add_10(num): return num + 10 add_10(10)

how to get your iq

def iq_test(numbers): nums = numbers.split(" ") evens = [] odds = [] for num in nums: if num % 2 == 0: evens.append(num) else: odds.append(num) if len(evens) > len(odds): return nums.index(odds[0]) + 1 else: return nums.index(evens[0]) + 1 iq_test("2 4 7 8 10")

def abc(): return "abcdefghijklmnopqrstuvwxyz" abc()

returns "abcdefghijklmnopqrstuvwxyz"

!!!

def add2(a, b): return a + b def add2(a, b, c): return add2(a, b) + c add2(1, 2, 3)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.

import time def fight(time_passed): food = 100 iron = 100 while True: if food == 0 or iron == 0: print("you died") break time.sleep(1) time_passed += 1 food -= 0.1 if time_passed % 100 == 0: iron -= 1 print(f"food: {food:.1f}, iron: {iron}") fight(0)

!!!

def square(a): return a * a

the 1 to 19 times table

def times_table(n): return [x*n for x in range(1, 20)] times_table(1)

mom

def mom(): print("You did a great job!") print("I'm proud of you.") print("I love you!") mom()

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def factory(time, food): for i in range(time): if food > 0: food = food - 1 else: return "you are dead" return food factory(120, 100)

251 GB Storage

def storage(gb): return f"You'll need {gb} GB to store all your selfies." storage(251)

the 1-999 times times table

def times_table(times): for i in range(1, 1000): print(f"{i} times {times} is {i*times}")

!!!

def print_kwargs(**kwargs): print(kwargs) print_kwargs(kwargs_1="Shark", kwargs_2=4.5, kwargs_3=True)

a tic tac toe game

def tic_tac_toe(): while True: move = get_players_move() if move == "quit": break make_move(move) if game_is_over(): announce_winner() break tic_tac_toe()

251 GB Storage

def disk_size_in_GB(size_in_TB): return size_in_TB * 1024 disk_size_in_GB(0.25)

the 1 to 19 times table

def times_table(times): for i in range(1, 20): print(f"{i} * {times} = {i * times}") times_table(4)

251 GB Storage

def convert_size(size_bytes): if size_bytes == 0: return "0B" size_name = ("B", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB") i = int(math.floor(math.log(size_bytes, 1024))) p = math.pow(1024, i) s = round(size_bytes / p, 2) return "%s %s" % (s, size_name[i]) convert_size(25165824000)

the 1 to 19 times table

def times_table(num): for i in range(1, 20): print(str(i) + " x " + str(num) + " = " + str(num * i)) times_table(5)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def food(x): return 100 - 10 * x def iron(x): return 100 - 100 * x def life(x, y, z): return food(x) - y, iron(x) - z life(10, 60, 100)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def food_timer(food,seconds): return food + int(seconds / 10) def iron_timer(iron,seconds): return iron + int(seconds / 100) def army_timer(food,seconds): return food - int(seconds / 60) def survival(food, iron, seconds): army = True while army: print(food,iron) food = food_timer(food,seconds) iron = iron_timer(iron,seconds) food = army_timer(food,seconds) if food <= 0: print('You are dead') army = False if iron <= 0: print('You lost the war') army = False survival(100,100,100000)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.

def army_supplies(food, iron, time_elapsed): total_food = food total_iron = iron while True: if time_elapsed % 10 == 0: total_food += 1 elif time_elapsed % 100 == 0: total_iron += 1 elif time_elapsed % 60 == 0: total_food -= 1 if total_food == 0: print("you died") break elif total_iron == 0: print("you died") break time_elapsed += 1 army_supplies(100, 100, 0)

motor(0,0)

c++

!!!

def add(a, b): sum = a + b print("The sum of {a} and {b} is {sum}".format(a = a, b = b, sum = sum)) add(1, 2)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def foodproduction(a): return a*10 def ironproduction(b): return b*100 def foodconsumption(c): return c*60 def supply(a1, b1, c1): food = 100 iron=100 while food>0 and iron>0: foodproduction(a1): ironproduction(b1): foodconsumption(c1): food = food - foodconsumption(c1) + foodproduction(a1) iron = iron - ironproduction(b1) if food <= 0: print("You ran out of food, you died") elif iron <= 0: print("You ran out of iron, you died") else: print("You survived")

251 GB Storage

def storage(gb): return gb * 1000 storage(251)

wow

def wow(a, b, c): return a * b * c wow(1, 2, 3)

GRADE 3 SASMO 2023 简体 （Examination time is:2023-04-08 14:00） 姓名:陈艾纶 准考证号:086230002639 手机:15300601005 There is still a long way to go 01 min 25 s Waiting for the exam

def grade_3(question_id,answer): if question_id == 1: if answer == "C": return 1 else: return 0 elif question_id == 2: if answer == "A": return 1 else: return 0 elif question_id == 3: if answer == "B": return 1 else: return 0 elif question_id == 4: if answer == "D": return 1 else: return 0 elif question_id == 5: if answer == "C": return 1 else: return 0 elif question_id == 6: if answer == "D": return 1 else: return 0 elif question_id == 7: if answer == "A": return 1 else: return 0 elif question_id == 8: if answer == "B": return 1 else: return

jhbgfygu

def jhbgfygu(a): return 'jhbgfygu' * a jhbgfygu(5)

!!!

def dummy(): return None print(dummy())

!!!

def add_unique(x, my_list = []): my_list.append(x) return my_list add_unique(1) add_unique(2) add_unique(3)

jhgfdftyuiyhgfdtygfc

def chk_odd(num): if num % 2 == 0: return True else: return False chk_odd(3)

251 GB Storage

def disk_space(space, unit): return space * 2**30 if unit.upper() == 'GB' else space * 2**20 disk_space(251, 'GB')

what

def what(n): if n > 0: return "pos" elif n < 0: return "neg" else: return "zero" what(-1)

motor(1,0)

!!!

def add(a, b): return a + b add(1, "2")

!!!

def function_name(parameters): """ Docstring explaining the function """ # Do stuff here # Return desired result

GRADE 3 SASMO 2023 简体 （Examination time is:2023-04-08 14:00） 姓名:陈艾纶 准考证号:086230002639 手机:15300601005 There is still a long way to go 01 min 25 s Waiting for the exam

def add(a, b): return a + b

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def army_survive(food, iron): time = 0 while True: if time % 10 == 0: food += 1 if time % 60 == 0: food -= 1 if food < 0: return "Your army died" if time % 100 == 0: iron += 1 if time % 60 == 0: iron -= 1 if iron < 0: return "Your army died" time += 1 army_survive(100, 100)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.

def army_supplies(time): iron = 100 food = 100 while time > 0: food -= 1 time -= 60 if time % 100 == 0: iron += 1 if time % 10 == 0: food += 1 if food <= 0: print('You died of hunger') return elif iron <= 0: print('You can not fight') return return food, iron

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def produce(food, iron): while food > 0: food = food - 1 print(food) iron = iron - 1 print(iron) produce(100, 100)

!!!

def add(a, b): return a + b add('1', 2)

the 1 to 19 times table

#include <stdio.h> int main() { int num; printf("Enter an integer: "); scanf("%d",&num); for(int i=1; i <= 10; ++i) { printf("%d * %d = %d \n", num, i, num*i); } return 0; }

the 1 to 19 times table

func times(n int) { for i := 1; i <= 19; i++ { fmt.Println(n, "x", i, "=", n*i) } }

Generate Function from description

def generate_function(description): pass gen_add = generate_function('add two numbers') gen_add(1, 2) # 3

import time import random print('you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food.') def ac (x,y) f=x i=y print('food:'f 'iron:'i) def gc (x) if f<=0: print('fail!')

Depending on the code, you might also need to use a semi-colon. ### How do I use a semi-colon? To use a semi-colon, you should use a semi-colon instead of a colon, and then `end` should be replaced with `;` For example:

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def army(food_p, iron_p): t = 0 while t < 60: if food > 0 and iron > 0: food = food + food_p iron = iron + iron_p food = food - 1 iron = iron - 1 else: print(t, "seconds,all dead") break t = t + 1 print(t, food, iron, "seconds")

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.The army eats 1 food every 60 sec.you decide how many food we produce.

def army(food, iron, seconds): while True: food -= 1 seconds += 60 if seconds % 10 == 0: food += 1 if seconds % 100 == 0: iron += 1 if food == 0 or iron == 0: print(food, iron) return army(food, iron, seconds) army(100, 100, 0)

you are helping an army. if you don't send supplies, you would die. if the food drops to 0 all would die. if you run out of iron, the army could not fight. you will start with 100 food and 100 iron. it takes 10 seconds to produce 1 food and 100 seconds to produce 1 iron.

def army_survival(food, iron): while(food > 0): print("You are still alive.") food = food - 1 iron = iron - 1 print("You have died.")

def add(a, b): return a + b def subtract(a, b): return a - b # use add and subtract to create the following functions def multiply(a, b): return a * b def divide(a, b): return a / b def square(a): return a * a