Múltiples de línea

id printLine(int n){
    for(int i = 0; i < n; i++){
        cout << "-";
    }
    cout << endl;
}

int main(){
    int n = 0;
    cin >> n;
    printLine(n);
    return 0;
}

A:

You can use a for loop to print the lines. The loop will run n