return list dictionary of the two biggest numbers in a list of dictionaries

def biggest_in_list(list_of_dicts):
  max1 = list_of_dicts[0]
  max2 = list_of_dicts[0]
  for i in list_of_dicts:
    if i['number'] > max1['number']:
      max2 = max1
      max1 = i
    elif i['number'] > max2['number']:
      max2 = i
  return [max1, max2]
    
biggest_in_list([{'name': 'A', 'number': 1}, {'name': 'B', 'number': 10}, {'name': 'C', 'number': 100}])