ingresar un numero de tres crifras  y hallar si es capicua o no

def capicua(x):
  reverse_number = 0
  n = x
  while n > 0:
    remainder = n % 10
    reverse_number = (reverse_number * 10) + remainder
    n //= 10
    
  if x == reverse_number:
    return 'capicua'
  else:
    return 'no capicua'
  
capicua(123)