Crear una suma de numeros complejos
def add(a,b):
return (a+b)
def sum_complex(*args):
sum_ = 0
for i in args:
sum_ = add(sum_, i)
return sum_
sum_complex(1,2,3,4,5,6)
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def add(a,b):
return (a+b)
def sum_complex(*args):
sum_ = 0
for i in args:
sum_ = add(sum_, i)
return sum_
sum_complex(1,2,3,4,5,6)
int add(int a, int b) {
return a + b;
}
def serie(resistencias):
total = 0
for resistencia in resistencias:
total += resistencia
return total
def paralelo(resistencias):
total = 0
for resistencia in resistencias:
if resistencia == 0:
return 0
total += 1 / resistencia
return 1 / total
def total(resistencias, tipo):
if tipo == "serie":
return serie(resistencias)
elif tipo == "paralelo":
return paralelo(resistencias)
else:
print("Tipo de resistencia no reconocida")
return None
resistencias = []
while True:
cantidad = int(input("Ingrese la cantidad de resistencias: "))
if cantidad > 0:
break
print("Ingrese una cantidad positiva")
for i in range(cantidad):
while True:
def hipotenusa(a, b):
return a**2 + b**2
hipotenusa(3, 4)
A:
Python 3.6+
The ** operator is a binary operator that can be used to raise a number to a power. It is equivalent to the ** operator in Python 2.7+, but is more readable and more efficient.
>>> 3 ** 2
tmp_file.close
#include<iostream>
#include<string>
using namespace std;
int main(){
int n;
cout<<"enter number: ";
cin>>n;
string str = to_string(n);
cout<<str<<endl;
cout<<"sum is: ";
int sum = 0;
for(int i = 0; i < str.length(); i += 2){
string s;
s += str[i];
s += str[i+1];
sum += stoi(s);
}
cout<<sum<<endl;
}
linkedHashMap.put(key, value)
def get_police_users(department):
import ldap
import re
from openpyxl import Workbook
from openpyxl import load_workbook
wb = Workbook()
ws = wb.active
# connect to active directory
conn = ldap.initialize('ldap://ldap.yourdomain.com')
# search for users in department in active directory
results = conn.search_s('dc=yourdomain,dc=com', ldap.SCOPE_SUBTREE, "department=" + department, ['cn'])
# create spreadsheet and add users in department to it
ws.append(["Users"])
for result in results:
ws.append([re.findall('(?<=cn=).*', result[1]['cn'][0].decode('utf-8'))[0]])
wb.save("output.xlsx")
# open spreadsheet and sort by last name
wb = load
#include<iostream>
using namespace std;
int main()
{
int a,b;
cin>>a>>b;
cout<<a+b<<endl;
}
int a, b;
Console.WriteLine("Dame dos numeros para dividirlos");
a = int.Parse(Console.ReadLine());
b = int.Parse(Console.ReadLine());
Console.WriteLine("El resultado de la división entera es {0}", DivEntera(a, b));
Console.WriteLine("El resultado de la división decimal es {0}", DivDecimal(a, b));
int DivEntera(int a, int b)
{
return a / b;
}
double DivDecimal(int a, int b)
{
return (double) a/b;
}